The number of possible straights are determined by the number of possible straight combos (10 as mentioned in the straight flush article) and the number of suit combos(4 suits pr. card, 4^5 combos)
n(straights) = suit combos * straight combos = 4^5 suit combos * 10 straights/suit combo = 10240 straights
40 of these straights are actually straight flushes, so there are 10200 ordinary straights. 1020 of these are ace-high straights, and there are obviously 1020 straights in each category(k-high, q-high and so on).
NB: 4^5 = 4*4*4*4*4 = 1024
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